Math, asked by srivastavshiv, 7 months ago

Two cross road each of width 6 m, cut at right angles through the centre of a rectangular park of
length 70 m and breadth 50 m and parallel to its sides. Find the area of the roads. Also find the
area of the park excluding cross roads.​

Answers

Answered by rakeshkumarbro218200
4

Answer:

A and B are two roads in the park.

area covered by road A=700×10(m

2

)

=7000 m

2

area covered by road B=300×10 m

2

=3000 m

2

Common area covered by road A and B=10×10 m

2

=100 m

2

area covered by roads =7000 m

2

+3000 m

2

−100 m

2

=10000 m

2

−100m

2

=9900 m

2

=0.99 hectare

area of the park =700×300 m

2

=210000 m

2

area of the park encluding cross Road =210000 m

2

−9900 m

2

=200100 m

2

=20.01 hectare

Answered by AVPRO
0

Answer:

The area of the park is 3500 m
The area of the park excluding the roads is 2780 m

Step-by-step explanation:

Area of the park= 70*50= 3500 m

Area of the roads= (6*70)+(6*50)

= 420+300

= 720 m

Area of the park excluding roads = 3500 - 720

= 2780 m

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