Math, asked by saddujethava, 3 months ago

two cross roads 2.5 m wide have been constructed in the middle of garden crossing each other at right angles, running parallel to the sides of the garden 35 m long and 20 m wide. find the cost of constructing the roads at the rate of rupees 100 per sq. m​

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Answers

Answered by poojarypavan006
0

Step-by-step explanation:

We have,

Length AB = 40 m and breadth BC = 25 m

∴ Area of lawn ABCD = 40 m x 25 m = 1000 m2

Length PQ = (40 + 2 + 2 ) m = 44 m

Breadth QR = ( 25 + 2 + 2 ) m = 29 m

∴ Area of PQRS = 44 m x 29 m = 1276 m2

Now,

Area of the path = Area of PQRS − Area of the lawn ABCD

= 1276 m2 − 1000 m2

= 276 m2

Rate of levelling the path = Rs. 8.25 per m2

∴ Cost of levelling the path = Rs. ( 8.25 x 276)

= Rs. 2277

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