Two cross roads 2.5 m wide have been constructed in the middle of a garden (3)
crossing each other at right angles, running parallel to the sides of the garden 35 m long and 20 m wide. Find the cost of constructing the roads at the rate of ₹ 100 per sq.m
Answers
Step-by-step explanation:
width =5 m
width =5 mlength of first parallel road 70 m
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.m
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.m
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25=550sqm
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25=550sqm
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25=550sqm
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25=550sqm cost of the construction per sq.m =Rs.105
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25=550sqm cost of the construction per sq.m =Rs.105total cost =550×105=Rs 57750