Two cross-roads 5m wide run parallel to the sides of a rectangular garden of length 45 m and width
40 m. Find the area of the cross-roads and also the cost of constructing these cross-roads at the rate
of 100 per square metre
Answers
Diameter of the circle = 42 m
Cost of cleaning per m² = ₹2.35
Cost of cleaning the whole field
where,
r = Radius
Radius =
According to the question by using the formula of Area of a Circle, we get,
⇢ Solving the above equation,
:
:
: ⟹ (
:
:
:
Cost of cleaning the field = ₹ (1,386 × 2.35)
:
Answer:
Solution:
Let ABCD be the rectangular park then EFGH and IJKL are the two rectangular roads with width 5m.
Given that length of rectangular park = 70m
Breadth of rectangular park = 45m
Area of the rectangular park = Length x Breadth
= 70 m x 45 m
= 3150 m²
Area of the road EFGH = 70 m x 5 m
= 350 m²
Now, Area of the road JKLI = 45 m x 5 m
= 225 m²
From the figure, it is clear that area of MNOP is common to the two roads.
Thus, Area of MNOP = 5 m x 5 m = 25 m²
Therefore,
Area of the roads = Area of EFGH + Area of JKLI – Area of MNOP
= (350 + 225) m2– 25 m²
= 550 m²
Again, it is given that the cost of constructing the roads = Rs. 105 per m²
Therefore,
Cost of constructing 550 m² area of the roads
= Rs. (105 x 550)
= Rs. 57750