two Cross Roads each of 2 metre wide run at right angles through the centre of a rectangular Park of 72 m by 48 M such that each is parallel to one of the sides of rectangle find the area of the remaining portion of the park
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Step-by-step explanation:
Area of first crssroad which is rectangular = l×b
Hence area = 72m × 2m= 144 m²
Area of 2nd crossroad whuch is rectangular = 48m× 2m
= 96 m²
Area of middle part which is square =2m×2m
= 4m^2
Area of crossroads= (144+96) m² - 4 m²
=240 m² - 4 m²= 236 m²
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