Question

Two cross-roads, each of 3 meters wide, run at right angle through the centre of a rectangular park of 60m by 42m such that each is parallel to one of the sides of the rectangle. find the area of the remaining portion of the park.​

Answer 1

Answer:

Step-by-step explanation:

Area of the park with crossroads = 60m * 42m

                                                       = 252$m^{2}$

Area of road along length = 60m * 3m

                                            = 180$m^{2}$

Area of road along breadth = 42m * 3m

                                              = 126$m^{2}$

Area of the common road = 3m * 3m

                                            = 9$m^{2}$

Area of the crossroads = ( 180$m^{2}$ + 126$m^{2}$ ) - 9$m^{2}$

                                       = 54$m^{2}$ - 9$m^{2}$

                                       =45$m^{2}$

Area of the remaining portion of the park = 252$m^{2}$ - 45$m^{2}$

                                                                     = 207$m^{2}$

Answer 2

Answer:

2223 square meter

Step-by-step explanation:

area of total rectangular part = l×b

= 60×42

= 2520 square meter

area of path= 60×3+42×3-3×3

= 180+126-9

= 306-9

= 297 square meter

area of remaining portion = 2520-297

= 2223 square meter