two cross roads, each of 3 meters wide, run at right angle through the centre of a rectangular park of 60 m by 42 m such that each parallel to one sides of the sides of the rectangle. Find the area of remaining portion of the park.
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Area of first cross road which is rectangle = l×b
Hence area =72m×3m=216m
2
Area of 2nd cross road which is rectangle =
=56m×3m=168m
2
Area of middle part which is square =3m×3m=9m
2
Area of cross roads =(216+168)m
2
−9m
2
=384m
2
−9m
2
=375m
2
I JUST TOOK ANOTHER DIGITS
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