two cross roads each of 5 m run at right angles through the centre of a rectangular lawn of legnth 50 m and breadth 40m parallel to its sides find the area of roads and area of the lawn excluding roads. give the awnser in hectares also find the cost of leveling the roads at the rate of 4.50 rupees per m2
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Answer:
1912.5 rupees
Step-by-step explanation:
width =5 m
length of first parallel road 50 m
area of first road 50×5=250 sq.m
length of second road 40 m
area of second road =40×5=200 sq.m
area of the common part of cross road with 5 m width that lies at the
center of the park 5×5 = 225 sq.m
area of roads = area of first road +area of second cross road−common area
=(250+200)−25
=450−25
=425 sqm
cost of the construction per sq.m =Rs. 4.50
total cost =425×4.50=Rs. 1912.5
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