Two cross roads,each of the width 10m,cut at right angles through the center of a rectangular park of length 700m and breadth 300m and parallel to its sides . Find the area of the roads . Also find the area of the park excluding cross roads . Give the answer in hectares
Answers
Answer: hey mate answer is 0.99 hectare and 20.01 hectare.
Step-by-step explanation:
Here, PQ = 10 m and PS = 300 m, EH = 10 m and EF =700 m and KL = 10 m and KN = 10 m.
Area of roads = Area of PQRS + Area of EFGH - Area of KLMN
[∵ KLMN is taken twice, which is to be subtracted ]
⇒ PS * PQ + EF * EH - KL * KN
⇒ [300*10] + [700*10] - [10*10]
⇒ 3000 + 7000 - 100
⇒ 9, 900 m^2
Area in hectares, 1 m^2 = 1/10000
∴ 9, 900 m^2 = 9900/10000 = 0.99 hectare.
Now , Area of park excluding cross roads = Area of park - Area of road
⇒ [ AB * AD ] - 9, 900
⇒ [ 700 * 300 ] - 9, 900
⇒ 2, 10, 000 - 9, 900
⇒ 2, 00, 100 m^2
⇒ 200100/10000 hectare = 20.01 hectare.
∴ Thus, area of road is 0.99 hectares and area of park excluding cross roads is 20.01 hectare.
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