Question

two cross roads each of the width 5m ,run at right angles through the centre of a rectangular pack of length 70m and breadth 35m and parallel to its side find area of roads also ,find the cost of constructing the roads also ,find the cost of constructing the roads at the rate of Rs65 per m²​

Answer 1

Answer

Given :-

•width =5 m

•length of first parallel road 70 m

Now,

area of first road = 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

Area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

Area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105

=Rs 57750

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Answer 2

$\huge\bf\colorbox{red}{Answer}$

width = 5m

length of first parallel road 70m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road = 45×5=225 sq.m

area of the common part of cross road with 5m width that lies at the

center of the park = 5×5 = 225 sq.m

area of roads = area of first road + area of second cross road - common area

= (350+225)-25

= 575-25

= 550sqm

cost of the construction per sq.m = Rs.105

total cost = 550×105

= Rs.57750

$\huge\mathcal\pink{Hope \: it \: helps \: you}$