Question

two cross roads, each of wide 10m,cut at right angles through the centre of a rectangular park of length 700m and breadth 300m and parallel to its sides. find the area of the roads .also find the area of the park excluding cross roads . give the answer in hectares


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Answer 1

Answer:

Step-by-step explanation:

Here, PQ=10=10m and PS=300=300m, EH=10=10m and EF=700=700m

And KL=10=10m and KN=10=10m

Area of roads==Area of PQRS++Area of EFGH-−Area of KLMN

[\because[∵ KLMN is taken twice, which is to be subtracted]]

=PS\times PQ+EF\times EH-KL+KN=PS×PQ+EF×EH−KL+KN

=(300\times 10)+(700\times 10)-(10\times 10)=(300×10)+(700×10)−(10×10)

=3000+7000-100=3000+7000−100

=9,900m^2=9,900m  

2

 

Area of road in hectares, 1m^2=\dfrac{1}{10000}1m  

2

=  

10000

1

​  

hectares

\therefore 9,900m^2=\dfrac{9900}{10000}=0.99∴9,900m  

2

=  

10000

9900

​  

=0.99 hectares

Now, Area of park excluding cross roads==Area of park-−Area of road

=(AB\times AD)-9,900=(AB×AD)−9,900

=(700\times 300)-9,900=(700×300)−9,900

=2,10,000-9,900=2,10,000−9,900

=2,00,100 m^2=2,00,100m  

2

 

=\dfrac{200100}{10000}=  

10000

200100

​  

 hectares=20.01=20.01 hectares.

solution