Math, asked by aditichauhan22, 11 months ago

two Cross Roads each of width 10 cut at right angles to the centre of a rectangular Park of length 700 and breadth 300 and parallel to its sides find the area of the roads also find the area of the park excluding crossroads give the answer in hectares​

Answers

Answered by missunknown07
36

Area of park= 700 * 300 = 210000 m2

If we take the horizontal road as road 1, its breadth is 10 m and length is 700 m.

So its area = 10 * 700 = 7000 m2

If we take the vertical road as road 2, its breadth is 10 m and length is 300 m.

So its area = 10 * 300 = 3000m2

Again, there is a small square at the centre caused by the intersection of the roads. The length of its side is 10 m.

So, its area = 10 * 10 = 100 m2

Now, total area of road = area of road 1 + area of road 2 - area of the small square at the centre.

= 7000 + 3000 - 100

= 10000 - 100

= 9900 m2

Since 10000 m2 = 1 hectare

=> 1 m2 = 1/10000 hectare

So, 9900 m2 = 9900/10000 = 0.99 hectare

So, the total area of roads is 0.99 hectare

Again, the area of park excluding crossroads = area of park - area of roads

= 210000 - 9900

= 200100 m2

Since 10000 m2 = 1 hectare

=> 1 m2 = 1/10000 hectare

So, 200100 m2 = 200100/10000 = 20.01 hectare

Hence, the area of park excluding crossroads = 20.01 hectare

Answered by sreejapramod2017
2

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