Math, asked by rishipelapudi, 4 months ago

Two cross roads, each of width 10 m, cut at right angles through the centre of a rectangular park of length 700 m and breadth 300 m and parallel to its sides. Find the area of the roads. Also find the area of the park excluding cross roads

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Answered by pratyush15899
27

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❥area of the roads=0.99 hectare

❥area of the park,

excluding cross roads= 20.01 hectare

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Given:

  • ABCD is a rectangle.
  • Length of park (l) = 700 m
  • Breadth of park (b) = 300 m

Solution:

⟹ Area of park ABCD= 700 × 300 = 210000 m^2

Length of road EFGH = 700 m

Length of road PQRS = 300 m

∵ Width of each road = 10 m.

∴ KLMN is a square of side 10 m.

Area of two roads =

  • area (EFGH) + area (PQRS) – area (KLMN)
  • = (700 × 10) + (300 × 10) – (10 × 10)
  • = 7000 + 3000 – 100
  • = 10000 – 100 = 9900 m2
  • = 990010000 hectare
  • = 0.99 hectare (∵ 1 hectare = 10000 m2)

Area of park excluding roads = 210000 – 9900

  • = 200100 m^2
  •  = 20010010000 hectare
  • = 20.01 hectare

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