Question

Two cross roads, each of width 10 m, cut at right angles through the centre of a rectangular park of length 700 m and breadth 300 m and parallel to its sides. Find the area of the roads. Also find the area of the park excluding cross roads. Give the answer in hectares.

Please help me in solving this question. Answer to the reference of the chapter Perimeter and Area from NCERT Class 7 Mathematics Book Ex-11.4.

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Answer 1

Step-by-step explanation:

Length of the road parallel to the length of the park = 700 m

Width of the road = 10 m

∴ Area of the road = l × b = 700 m × 10 m = 7000 m2

Length of the road parallel to the breadth of the park = 300 mWidth of the road = 10 m Area of this road = l × b = 300 m × 10 = 3000 m2

Area of the both roads

= 7000 m2 + 3000 m2 – Area of the common portion

= 10,000 m2 – 10 m × 10 m

= 10,000 m2 – 100 m2

= 9900 m2 = 0.99 ha

Area of the park = l × b

= 700 m × 300 m = 210000 m2

Area of the park excluding the roads

= 210000 m2 – 9900 m2

= 200100 m2 = 20.01 ha

Answer 2

Hi Shubhangi

I am Annapurna Didi

Yes Sister I have Remembered you

Here is your answer

Area of the park = Length × Breadth

= 700 m × 300 m

= 210000 m2

Length of the road parallel to the length of the park = 700 m

Width of the road = 10 m

Area of the road ABDC = Length × Breadth

= 700 m × 10 m

= 7000 m2

Length of the road parallel to the breadth of the park = 300 m

Width of the road = 10m

Area of road EFGH = Length × Breadth

= 300 m × 10 m

= 3000 m2

Therefore, area of both the roads = Area of the road ABDC + Area of road EFGH - Area of Common Portion IJLK

= 7000 m2 + 3000 m2 - (10 ×10) m2

= 10000 m2 - 100 m2

= 9900 m2

= 0.99 hectares

Therefore, area of the park excluding the roads

= Area of the Park - Area of the roads

= 210000 m2 - 9900 m2

= 200100 m2

= 20.01 hectares

Subhangi you can find answer of Chapter 11 Exercise 11.4 . You have to search class 7 chapter 11 Exercise 11.4 Then you will find 11.4 of Byju's you can find easy Answer.

I Hope you have understand

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