Two cross roads, each of width 10 m, run at right angles through the centre of a
rectangular park of length 90 m and breadth 65 m and parallel to its sides. Find
the area of the roads. Also find the cost of constructing the roads at the rate of Rs
75 per m2
.
Answers
Answer:
Width = 10m
Length of first parallel road = 90m
area of first road = 90×10 = 900m²
Length of second road = 65m
Area of second road = 65×10 = 650m²
area of the common part of cross road with 10 m width that lies at the center of the park 10×10 = 100 sq.m
area of roads = area of first road +area of second cross road−common area
= ( 900 + 650 ) - 100
= 1550 - 100
= 1450 sq.m
cost of the construction per sq.m =Rs.75
total cost = 1450×75 = Rs 1,08,750
Answer:
Answer:
Width = 10m
Length of first parallel road = 90m
area of first road = 90×10 = 900m²
Length of second road = 65m
Area of second road = 65×10 = 650m²
area of the common part of cross road with 10 m width that lies at the center of the park 10×10 = 100 sq.m
area of roads = area of first road +area of second cross road−common area
= ( 900 + 650 ) - 100
= 1550 - 100
= 1450 sq.m
cost of the construction per sq.m =Rs.75
total cost = 1450×75 = Rs 1,08,750
Step-by-step explanation:
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