Question

Two cross roads, each of width 10m, cut at right angle
through the centre of a rectangular park of length 600m and
breadth 400m and parallel to its sides. Find
(i) Area of the road ABCD.
(ii) Area of the road PQRS.
(iii) Area of the Junction.
(iv) Area occupied by the roads.
(v) Cost of cementing the roads at `20per m2

Answer 1

Answer:

Here, PQ=10m and PS=300m, EH=10m and EF=700m

And KL=10m and KN=10m

Area of roads = Area of PQRS+Area of EFGH−Area of KLMN

[∵ KLMN is taken twice, which is to be subtracted]

=PS×PQ+EF×EH−KL×KN

=(300×10)+(700×10)−(10×10)

=3000+7000−100

=9,900m

2

Area of road in hectares, 1m

2

=

10000

1

hectares

∴9,900m

2

=

10000

9900

=0.99 hectares

Now, Area of park excluding cross roads = Area of park−Area of road

=(AB×AD)−9,900

=(700×300)−9,900

=2,10,000−9,900

=2,00,100 m

2

=

10000

200100

hectares=20.01 hectares.

Hope it helps u ☺