Math, asked by farzanaSayed, 4 months ago

two cross roads each of width 10m cut at right angles through the centre of a rectangular park of length 700m and breadth 300m and parallel to it's sides find the area of the roads and also the cost of constructing the roads at the rate of rs110per m square​ pls tell the answer exams are going on​

Answers

Answered by rohittiwari3957
1

Step-by-step explanation:

Here, PQ=10m and PS=300m, EH=10m and EF=700m

And KL=10m and KN=10m

Area of roads = Area of PQRS+Area of EFGH−Area of KLMN

[∵ KLMN is taken twice, which is to be subtracted]

=PS×PQ+EF×EH−KL×KN

=(300×10)+(700×10)−(10×10)

=3000+7000−100

=9,900m

2

Area of road in hectares, 1m

2

=

10000

1

hectares

∴9,900m

2

=

10000

9900

=0.99 hectares

Now, Area of park excluding cross roads = Area of park−Area of road

=(AB×AD)−9,900

=(700×300)−9,900

=2,10,000−9,900

=2,00,100 m

2

=

10000

200100

hectares=20.01 hectares.

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