Two cross roads, each of width 3 m, run at right angles through the
centre of a rectangular park of length 90 m and breadth 60 m and
parallel to its sides. Find the area of the roads. Also find the cost of
constructing the roads at the rate of Rs 110 per 2
.
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Answer:
Length of first parallel road = 90 m
width = 3 m
Area of first road = 90 x 3
= 270 m²
Length of second road = 60 m
Area of second road = 60 x 3
= 180 m²
Area of the common part of cross road with 5 m width that lies at the center of the park = 3 x 3 = 9 m²
Area of roads = Area of first road + Area of second cross road − Common area
= (270 + 180) - 9
= 90 - 9
= 81 m²
Cost of the construction per m² = Rs. 110
Total cost = 81 x 110
= Rs. 8910
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