Math, asked by gokulkrishnanjan9, 5 months ago

Two cross roads, each of width 3 m, run at right angles through the

centre of a rectangular park of length 90 m and breadth 60 m and

parallel to its sides. Find the area of the roads. Also find the cost of

constructing the roads at the rate of Rs 110 per 2

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Answers

Answered by DeshnaSharma
2

Answer:

Length of first parallel road = 90 m

width = 3 m

Area of first road = 90 x 3

                            = 270 m²

Length of second road = 60 m

Area of second road = 60 x 3

                                   = 180 m²

Area of the common part of cross road with 5 m width that lies at the  center of the park = 3 x 3 = 9 m²

Area of roads = Area of first road + Area of second cross road − Common area

                       = (270 + 180) - 9

                       = 90 - 9

                       = 81 m²

Cost of the construction per m² = Rs. 110

Total cost = 81 x 110

                = Rs. 8910

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