Two cross roads each of width 4m, run at right anglers through the center of the park of length 65m and breadth 45m and parallel to its sides.Also find the cost of constructing the roads at a rate of Rs.500 per 10sq. m.
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Area prll to length
length=65 m
breadth=4m
area=l×b
65×4
=260m sq.
Area prll to breadth
length=4m
breadth=45m
area=l×b
=4×45
=180 m sq.
Common area
side=4m
area=s×s
=4×4
=16m sq.
area of roads=Area prll to length+Area prll to breadth-common area
=260+180-16
=424
cost of constructing road 10 m sq.=₹500
cost of constructing roads per m sq.=500÷10
cost of constructing roads 424m sq.=500÷10×424
=₹21200
if this is the required ans., pls mark as brainliest
length=65 m
breadth=4m
area=l×b
65×4
=260m sq.
Area prll to breadth
length=4m
breadth=45m
area=l×b
=4×45
=180 m sq.
Common area
side=4m
area=s×s
=4×4
=16m sq.
area of roads=Area prll to length+Area prll to breadth-common area
=260+180-16
=424
cost of constructing road 10 m sq.=₹500
cost of constructing roads per m sq.=500÷10
cost of constructing roads 424m sq.=500÷10×424
=₹21200
if this is the required ans., pls mark as brainliest
sparshsmarty05:
thanks'
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