Question

Two cross roads, each of width 5 m, cut at right angles through the centre of a rectangular park of length 300 m and breadth 150 m and parallel to its sides. What is the area of the roads? ​

Answer 1

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width = 5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m 

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that  lies at the 

center of the park 5×5 = 225 sq.m 

area of roads = area of first road +area of second cross road−common area

                                           =(350+225)−25=575−25=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

Answer 2

Answer:

Width = 5

Area of first road = 300×150=45000m sq

Area of the second road =300×150=45000 m sq

Area of both roads =45000+45000=90000000

Step-by-step explanation:

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Shibam Gope