Math, asked by sunilprsd5, 10 months ago

Two cross roads, each of width 5 m, run at right angles through the centre
of a rectangular park of length 70 m and breadth 45 m and parallel to;
sides. Find the area of the roads. Also find the cost of constructing the
roads at the rate of 105 per m².​

Answers

Answered by vivinvikranth19
2

Answer:

Step-by-step explanation: area of 1st road=70*5=350m^2

Area of 2 Nd road= 45*5= 225m^2

A of cross section.......5*5....25

A or road.....350+225-25.......550m^2

Answered by manoj246923
14

Answer:

area of 1st road =l×b

=45×5

=225

area of 2nd road =l×b

=70×5

350

area of common square =5×5=25

area of the roads =225+350 -25

=550

cost of construction of roads at the rate 105=105×550

=10500

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