Math, asked by yashikabhargava05, 11 months ago

Two cross roads, each of width 5 m, run at right angles through the centre
of a rectangular park of length 70 m and breadth 45 m and parallel to its
sides. Find the area of the roads. Also find the cost of constructing the
roads at the rate of 105 per m².​

Answers

Answered by omprakashmalviya2000
27

Answer:

Step-by-step explanation:

{Refer to the attachment diagram for convenience...}

Length of the Rectangular park (BC): 70m.

Breadth of the Rectangular park (AB): 45m.

Area of the Rectangular park (ABCD): (l × b) unit

→70 × 45

→3150 sq. m.

Length of vertical road (JK): 45m.

Breadth of vertical road (IJ): 5m.

Area of vertical road (IJKL): (l × b) unit

→45 × 5

→225 sq. m.

Lenght of the horizontal road (YZ): 70m.

Breadth of the horizontal road (ZW): 5m.

Area of the horizontal road (WXYZ): (l + b) unit

→70 × 5

→350 sq. m.

Side of the overlapping roads (GH): 5m.

Area of the overlapping roads (EFGH): (s^2) unit

→5^2

→25 sq. m.

Total Area of the roads (Excluding the overlapping roads): Area of (XYZW) + (IJKL) - (EFGH)

→225 + 350 - 25

→550 sq. m.

Rate of cost of constructing roads per sq. m.: 105.

Total cost of constructing the roads: 105 × 550

→57750

Hence, the cost of constructing the roads is 57750.

{All the sides taken are given in the attachment diagram...}

{Hope it helped you...}

{Kindly Mark as Brainliest...}

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