Question

Two cross roads, each of width 5 m, run at right angles through the center of a rectangular park of

length 70 m and breadth 45 m parallel to its sides. Find the area of the roads. Also, find the cost of

constructing the roads at the rate of Rs 105 per m2

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Answer 1

Step-by-step explanation:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

Answer 2

Step-by-step explanation:

Width =5 m

Length of first parallel road 70 m

Area of first road 70×5=350 sq.m

Length of second road 45 m

Area of second road =45×5=225 sq.m

Area of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m

Area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

Cost of the construction per sq.m =Rs.105

Total cost =550×105=Rs 57750

Hope it helps you