Question

Two Cross Roads each of width 5 metre run at right angles through the centre of a rectangular Park of length 700 and with 300 parallel to its side find the area of the road also find the cost of constructing the roads at the rate of rupee 105 per metre square ​

Answer 1

Your Answer is in the Attachment ✌️☺️❤️

Answer 2

Given that length of rectangular park

= 70m Breadth of rectangular park = 45m

Area of the rectangular park

= Length x Breadth = 70 m x 45 m = 3150 m2 Area of the road EFGH = 70 m x 5 m = 350 m2 Now, Area of the road JKIL = 45 m x 5 m = 225 m2 From the figure, it is clear that area of MNOP is common to the two roads. Thus, Area of MNOP = 5 m x 5 m = 25 m2 Therefore, Area of the roads = Area of EFGH + Area of JKIL – Area of MNOP = (350 + 225) m2– 25 m2 = 550 m2 Again, it is given that the cost of constructing the roads = Rs. 105 per m2 Therefore,

Cost of constructing 550 m2 area of the roads = Rs. (105 x 550) = Rs. 57750.