Question

Two Cross Roads each of width 5 metre run at right angles through the centre of a rectangular Park of length 17 and breadth 45 metres and parallel to its sides find the area of road also find the cost constructing the roads at of rupees 105 per metre square draw a figure also

Answer 1

Answer:

Solution:-

Length of the 1st cross road parallel to the length = 70 m

Breadth of the 1st cross road parallel to the length = 5 m

Area of the 1st cross road = 70×5 

= 350 sq m

Length of the 2nd cross road parallel to the breadth = 45 m

Breadth of the 2nd cross road parallel to the breadth = 5 m

Area of the 2nd cross road = 45×5 

= 225 sq m

Area of the common part of the 2 cross roads with width 5 m that lies at the center of the rectangular park = 5×5

 

= 25 sq m

Area of the 2 cross roads = Area of the 1st cross road + Area of the 2nd cross road - Common area

⇒ (350 + 225) - 25

⇒ 575 - 25 

= 550 sq m

Cost of constructing the roads = Rs. 105 sq m

Total cost of constructing the road = 550×105

= Rs. 57750

Answer 2

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width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750