Two cross roads, each of width 5m, run at right angles through the centre of a rectangular park of length 70m and breadth 45m and parallel to its sides. Find the area of the roads . Also find the cost of constructing the roads at the rate of ₹105 per m square
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- Length of the 1st cross road parallel to the length = 70 m
- Breadth of the 1st cross road parallel to the length = 5 m
- Area of the 1st cross road = 70*5
- = 350 sq m
- Length of the 2nd cross road parallel to the breadth = 45 m
- Breadth of the 2nd cross road parallel to the breadth = 5 m
- Area of the 2nd cross road = 45*5
- = 225 sq m
- Area of the common part of the 2 cross roads with width 5 m that lies at the center of the rectangular park = 5*5
- = 25 sq m
- Area of the 2 cross roads = Area of the 1st cross road + Area of the 2nd cross road - Common area
- ⇒ (350 + 225) - 25
- ⇒ 575 - 25
- = 550 sq m
- Cost of constructing the roads = Rs. 105 sq m
- Total cost of constructing the road = 550*105
- = Rs. 57750
- Answer.
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➥57,750.
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