Question

two cross roads each of width 5m run at right angles through the centre of a rectangular park of length 70m and breadth 45m parallel to its sides.Find the area of the roads .Also find the cost of constructing the roads at the rate of Rs 105 perm

Answer 1

Solution:-

Length of the 1st cross road parallel to the length = 70 m
Breadth of the 1st cross road parallel to the length = 5 m

Area of the 1st cross road = 70*5 

= 350 sq m

Length of the 2nd cross road parallel to the breadth = 45 m
Breadth of the 2nd cross road parallel to the breadth = 5 m

Area of the 2nd cross road = 45*5 

= 225 sq m

Area of the common part of the 2 cross roads with width 5 m that lies at the center of the rectangular park = 5*5
 
= 25 sq m

Area of the 2 cross roads = Area of the 1st cross road + Area of the 2nd cross road - Common area

⇒ (350 + 225) - 25

⇒ 575 - 25 

= 550 sq m

Cost of constructing the roads = Rs. 105 sq m

Total cost of constructing the road = 550*105

= Rs. 57750

Answer.

Answer 2

Answer:

Length of the 1st cross road parallel to the length = 70 m

Breadth of the 1st cross road parallel to the length = 5 m

Area of the 1st cross road = 70*5 

= 350 sq m

Length of the 2nd cross road parallel to the breadth = 45 m

Breadth of the 2nd cross road parallel to the breadth = 5 m

Area of the 2nd cross road = 45*5 

= 225 sq m

Area of the common part of the 2 cross roads with width 5 m that lies at the center of the rectangular park = 5*5

 

= 25 sq m

Area of the 2 cross roads = Area of the 1st cross road + Area of the 2nd cross road - Common area

⇒ (350 + 225) - 25

⇒ 575 - 25 

= 550 sq m

Cost of constructing the roads = Rs. 105 sq m

Total cost of constructing the road = 550*105

= Rs. 57750

Step-by-step explanation: