Question

Two Cross roads each of width 5m run at right angles through the centre of a rectangular park of length 70m and breadth 45m and parallel its sides .find the area of roads

Answer 1

area of first road = 5m X 70m
                           = 350m square
area of second road = 5m X 45m
                                 = 225m square
area of the region common in both the roads = 5m X 5m
                                                                        = 25m square
therefore, area of both the roads = (225m2 + 350m2) - 25m2
                                                     = 550m2

Answer 2

Answer:

Here You Go Mate :-

Explanation:

Area Of 1st Road =

=> 45 x 5

=>225 sq. m

Area of 2nd Road =

=>70 x 5

=>350 sq. m

NOTE : As they roads are over lapping in the centre we need to minus the square in the middle. Area of the Square = 5 x 5 = 25

Therefore, total area is 225 + 250 - 25 = 550 sq. m