Question

Two cross roads, each of width 5m, run at right angles through the centre of a rectangular
park of length 80m and breadth 50m and parallel to its sides. Find the area of the roads.​

Answer 1

Step-by-step explanation:

Given that length of rectangular park = 70m Breadth of rectangular park = 45m Area of the rectangular park = Length x Breadth = 70 m x 45 m = 3150 m2 Area of the road EFGH = 70 m x 5 m = 350 m2 Now, Area of the road JKIL = 45 m x 5 m = 225 m2 From the figure, it is clear that area of MNOP is common to the two roads. Thus, Area of MNOP = 5 m x 5 m = 25 m2 Therefore, Area of the roads = Area of EFGH + Area of JKIL – Area of MNOP = (350 + 225) m2– 25 m2 = 550 m2 Again, it is given that the cost of constructing the roads = Rs. 105 per m2 Therefore, Cost of constructing 550 m2 area of the roads = Rs. (105 x 550) = Rs. 57750.