Math, asked by harshit19172, 3 months ago

Two cross roads each of width 5m runs at right angles through the centre of a rectangle park lengh 80 and breadth 35 and Parralel to its side. Find the area of the roads​

Answers

Answered by gbarman74
4

Step-by-step explanation:

Answer

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

Similar questions