Question

two Cross Roads, each of width20m cut at right angles through the centre of rectangular Park of length 800m and breadth 400m and parallel to its sides. find the area of roads.and also find the area of park excluding cross roads. please tell me answer plz please ​

Answer 1

Answer:

_________________

ANSWER

_________________

Here, PQ=10m and PS=300m, EH=10m and EF=700m

And KL=10m and KN=10m

Area of roads = Area of PQRS+Area of EFGH−Area of KLMN

[∵ KLMN is taken twice, which is to be subtracted]

=PS×PQ+EF×EH−KL×KN

=(300×10)+(700×10)−(10×10)

=3000+7000−100

=9,900m

2

Area of road in hectares, 1m

2

=

10000

1

hectares

∴9,900m

2

=

10000

9900

=0.99 hectares

Now, Area of park excluding cross roads = Area of park−Area of road

=(AB×AD)−9,900

=(700×300)−9,900

=2,10,000−9,900

=2,00,100 m

2

=

10000

200100

hectares=20.01 hectares.

Answer 2

Answer:

area of roads is 23600 and area of park excluding crossroads is 296400

Step-by-step explanation:

The area of crossroads would be (20*800+400)-400

-400 as There will be an overlapping area so there will bge and additional 400 if you dont minus it. and park area is easy after this