Question

Two cross roads each width 10cm, cut at right angles through the centre of a rectangular park of length 700m and breadth 300m and parallel to its sides area of the excluding cross roads?​

Answer 1

Step-by-step explanation:

200100/1000=

hectares=20.01 hectares.

Answer 2

Here, PQ=10m and PS=300m, EH=10m and EF=700m

Here, PQ=10m and PS=300m, EH=10m and EF=700mAnd KL=10m and KN=10m

Here, PQ=10m and PS=300m, EH=10m and EF=700mAnd KL=10m and KN=10mArea of roads = Area of PQRS+Area of EFGH−Area of KLMN

Here, PQ=10m and PS=300m, EH=10m and EF=700mAnd KL=10m and KN=10mArea of roads = Area of PQRS+Area of EFGH−Area of KLMN[∵ KLMN is taken twice, which is to be subtracted]

Here, PQ=10m and PS=300m, EH=10m and EF=700mAnd KL=10m and KN=10mArea of roads = Area of PQRS+Area of EFGH−Area of KLMN[∵ KLMN is taken twice, which is to be subtracted]=PS×PQ+EF×EH−KL×KN

Here, PQ=10m and PS=300m, EH=10m and EF=700mAnd KL=10m and KN=10mArea of roads = Area of PQRS+Area of EFGH−Area of KLMN[∵ KLMN is taken twice, which is to be subtracted]=PS×PQ+EF×EH−KL×KN=(300×10)+(700×10)−(10×10)

Here, PQ=10m and PS=300m, EH=10m and EF=700mAnd KL=10m and KN=10mArea of roads = Area of PQRS+Area of EFGH−Area of KLMN[∵ KLMN is taken twice, which is to be subtracted]=PS×PQ+EF×EH−KL×KN=(300×10)+(700×10)−(10×10)=3000+7000−100

Here, PQ=10m and PS=300m, EH=10m and EF=700mAnd KL=10m and KN=10mArea of roads = Area of PQRS+Area of EFGH−Area of KLMN[∵ KLMN is taken twice, which is to be subtracted]=PS×PQ+EF×EH−KL×KN=(300×10)+(700×10)−(10×10)=3000+7000−100=9,900m²

Area of road in hectares, 1m²= 1 hectares

10000

∴9,900m²= 9900 0.99 hectares

10000

Now, Area of park excluding cross roads = Area of park−Area of road

Now, Area of park excluding cross roads = Area of park−Area of road=(AB×AD)−9,900

Now, Area of park excluding cross roads = Area of park−Area of road=(AB×AD)−9,900=(700×300)−9,900

Now, Area of park excluding cross roads = Area of park−Area of road=(AB×AD)−9,900=(700×300)−9,900=2,10,000−9,900

Now, Area of park excluding cross roads = Area of park−Area of road=(AB×AD)−9,900=(700×300)−9,900=2,10,000−9,900=2,00,100 m²

200100 hectares=20.01 hectares.

10000

Hope it's helpful ☺️