Question

Two cross roads each with width 4m runs at an right angle through the center of the rectangular park of length 100m and breadth 60m which is parallel to its sides find the area of the roads and also find cost of constructing the road at the rate of rupees 80 per m​

Answer 1

$\huge\boxed{\fcolorbox{red}{yellow}{Shailesh}}$

$\bf\huge\underline\pink{Solution:-}$

Length of the 1st cross road parallel to the length = 70 m

Breadth of the 1st cross road parallel to the length = 5 m

Area of the 1st cross road = 70*5 

= 350 sq m

Length of the 2nd cross road parallel to the breadth = 45 m

Breadth of the 2nd cross road parallel to the breadth = 5 m

Area of the 2nd cross road = 45*5 

= 225 sq m

Area of the common part of the 2 cross roads with width 5 m that lies at the center of the rectangular park = 5*5

 

= 25 sq m

Area of the 2 cross roads = Area of the 1st cross road + Area of the 2nd cross road - Common area

⇒ (350 + 225) - 25

⇒ 575 - 25 

= 550 sq m

Cost of constructing the roads = Rs. 105 sq m

Total cost of constructing the road = 550*105

= Rs. 57750

$\bf\huge\underline\red{Follow me}$

Answer 2

$\huge\star\mathfrak\blue{{Answer:-}}$

Length of the 1st cross road parallel to the length = 70 m

Breadth of the 1st cross road parallel to the length = 5 m

Area of the 1st cross road = 70*5

= 350 sq m

Length of the 2nd cross road parallel to the breadth = 45 m

Breadth of the 2nd cross road parallel to the breadth = 5 m

Area of the 2nd cross road = 45*5

= 225 sq m

Area of the common part of the 2 cross roads with width 5 m that lies at the center of the rectangular park = 5*5

= 25 sq m

Area of the 2 cross roads = Area of the 1st cross road + Area of the 2nd cross road - Common area

⇒ (350 + 225) - 25

⇒ 575 - 25

= 550 sq m

Cost of constructing the roads = Rs. 105 sq m

Total cost of constructing the road = 550*105

= Rs. 57750