Math, asked by geetakathare27, 3 months ago


Two cross
roads of a
rectangular park each of
width 3m, at right
angles through the centre
of a park of length 48m
and breadth -32m and
parallel to its sides. Find
the area of the cross roads.
Also find the cost of
constructing roads at the
rate of Rs 250 per sq.m.


plz answer step by step ​

Answers

Answered by 255khushboosingh
3

Answer:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

Step-by-step explanation:

i hope you will understand

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