Math, asked by ruparupa176, 3 months ago

Two cross roads of width 3m runs through the middle of the garden of length 100m and breadth 80m
a) The area of the garden is ____________________.
b) The area of the crossroads is ________________________.
c) Cost of paving the roads at the rate of ₹20 per m2
is ___________.

Answers

Answered by keerthanamatheswaran
0

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m 

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that  lies at the 

center of the park 5×5 = 225 sq.m 

area of roads = area of first road +area of second cross road−common area

                                           =(350+225)−25=575−25=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

Answered by swikairachan
0

Answer:

a. area = length× breadth= 100 × 80 = 8000m²

b. area of crossroads = 2 ×( 100 × 3) = 600m²

c. cost = 600 × 20 = ₹12,000.

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