Two cross roads of width 3m runs through the middle of the garden of length 100m and breadth 80m
a) The area of the garden is ____________________.
b) The area of the crossroads is ________________________.
c) Cost of paving the roads at the rate of ₹20 per m2
is ___________.
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width =5 m
length of first parallel road 70 m
area of first road 70×5=350 sq.m
length of second road 45 m
area of second road =45×5=225 sq.m
area of the common part of cross road with 5 m width that lies at the
center of the park 5×5 = 225 sq.m
area of roads = area of first road +area of second cross road−common area
=(350+225)−25=575−25=550sqm
cost of the construction per sq.m =Rs.105
total cost =550×105=Rs 57750
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Answer:
a. area = length× breadth= 100 × 80 = 8000m²
b. area of crossroads = 2 ×( 100 × 3) = 600m²
c. cost = 600 × 20 = ₹12,000.
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