Question

Two cross rods, each of width 3 m , run at right angles through the center of rectangular park of lenght 60m and breadth 33m and parallel of its sides. Find the area of roads . Also find the cost of constructing the road at the rate of ₹ 100 per m².


Please give full answer with full solution ...
its my humble request ​

Answer 1

width =3 m

length of first parallel road 60 m

area of first road 60×3=180 sq.m

length of second road 33 m

area of second road =33×3=99 sq.m

area of the common part of cross road with 3 m width that lies at the

center of the park 3×3 = 9 sq.m

area of roads = area of first road +area of second cross road−common area

=(180+99)−9

=270 sqm

cost of the construction per sq.m = 100

total cost (100× 270) = 27000 tk