Math, asked by abhishekneg4, 2 months ago

Two cross yards each of width 3 m run at right angles through the centre of a rectangular park of length 60m and breadth 33m and parrallel to its side Find the area of roads Also find the cost of constructing the roads at the rate of Rs 100 per m^2

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Answers

Answered by ardraraj222007
0

Answer:

Cost is Rs. 57750

Step-by-step explanation:

Width =5 m

length of first parallel road 70 m

area of first road 70 × 5 = 350 sq.m

length of second road 45 m  

area of second road = 45 × 5 = 225 sq.m

area of the common part of cross road with 5 m width that  lies at the  

Center of the park 5 × 5 = 225 sq.m  

area of roads = area of first road + area of second cross road − common area                                          

= ( 350 + 225 ) − 25

= 575 − 25

= 550 sq m .

cost of the construction per sq.m = Rs.105

Total cost = 550 × 105 = Rs. 57750

                        I hope this answer will help you...........

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