Two crossroads, as shown in fig.2, each of width 5m, run through the centre of a rectangular park of length 75m and breadth 55m. Find the area of the paths.
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1
Answer:
625
Step-by-step explanation:
Area of the paths = Area of path 1 + Area of path 2 - Common area of the intersection of both paths
=75×5 + 55× 5 - 5×5
= 625
Answered by
1
Answer:
Answer
width =5 m
length of first parallel road 70 m
area of first road 70×5=350 sq.m
length of second road 45 m
area of second road =45×5=225 sq.m
area of the common part of cross road with 5 m width that lies at the
center of the park 5×5 = 225 sq.m
area of roads = area of first road +area of second cross road−common area
=(350+225)−25
=575−25
=550sqm
cost of the construction per sq.m =Rs.105
total cost =550×105=Rs 57750
hope it"s work.
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