Question

Two crossroads each 3m wide cut at right angles through the centre of a rectangular park 72m by 56m, such that each is parallel to one the sides of rectangle . find the area of the remaining area of the park.
Please answer fast

Answer 1

➡️Answer:The area of the remaining area of the park is 3657 sq-m

➡️Solution:

Area of Rectangular park
$l = 72 \: m \\ b = 56 \: m \\ \\ l \times b = 72 \times 56 \\ \\ = 4032 \: {m}^{2}$
Since both the cross roads are also rectangles of
$l = 3 \: m \\\\ b = 56 \\ \\ area \: = 56 \times 3 = 168 {m}^{2}$

area of second road
$l = 3 \: m \\ \\b = 72m \\ area = 72 \times 3 \\ = 216 \: {m}^{2}$

Area of common square =
$3 \times 3 = 9 \: {m}^{2}$

Area of the remaining area of the park = Area of park-area of road1-area of road2+ area of square

➡️➡️Since, area of square repeat twice and subtracted twice,hence adding one time

$= 4032 - 168 - 216 + 9 \\ \\ = 3657 \: {m}^{2}$

area of remaining park is 3657 sq-m.

Hope it helps you.

Answer 2

Step-by-step explanation:

Answer:The area of the remaining area of the park is 3657 sq-m

➡️Solution:

Area of Rectangular park

\begin{gathered}l = 72 \: m \\ b = 56 \: m \\ \\ l \times b = 72 \times 56 \\ \\ = 4032 \: {m}^{2} \\ \end{gathered}l=72mb=56ml×b=72×56=4032m2

Answer:The area of the remaining area of the park is 3657 sq-m

➡️Solution: