Question

Two crossroads, each of the width 3m, cut at right angles through the centre of a rectangular park of length 20m and breadth 16m. Find the area of the paths and the area of the park that is not covered by the paths? 3​

Answer 1

Answer:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that  lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

                                           

=(350+225)−25

=575−25

=550sqm

​

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

Explanation:

Answer 2

Answer:

area of path= 99m

area of remaining park = 221m

maybe

Explanation:

first we find the area of the whole park including Road= 16×20= 320

the area of first road= 20×3=60

the area of second road= 16×3=48

area of square center of the road= 3×3= 9

the 60+48= 108

then= 108-9= 99 area of road

now,= area of whole park (-) area of road= 320-99=221

hope it works