Question

Two crossroads each of width 10m, run through the center of a rectangular park of length 75m and breadth 55m. The area of the path is _____sq.m *

Answer 1

Answer:

5 m

Step-by-step explanation:

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that  lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

                                           

=(350+225)−25

=575−25

=550sqm

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