Question

· Two crossroads, each of width 15 m constructed at right-angles through the centre of a rectangular garden of length 500 m and breadth 200 m are parallel to its sides. Find the area of the roads.​

Answer 1

Here, PQ=10m and PS=300m, EH=10m and EF=700m

And KL=10m and KN=10m

Area of roads = Area of PQRS+Area of EFGH−Area of KLMN

[∵ KLMN is taken twice, which is to be subtracted]

=PS×PQ+EF×EH−KL×KN

=(300×10)+(700×10)−(10×10)

=3000+7000−100

=9,900m2

Area of road in hectares, 1m2=100001hectares

∴9,900m2=100009900=0.99 hectares

Now, Area of park excluding cross roads = Area of park−Area of road

=(AB×AD)−9,900

=(700×300)−9,900

=2,10,000−9,900

=2,00,100 m2

=10000200100 hectares=20.01 hectares.