Question

Two crossroads, each of width 4 m, run at right
angles through the centre of a rectangular
park of length 74 m and breadth 48 m. Find
the
(a) area of the crossroads.
(b) cost of cementing the roads at 110 per
m?​

Answer 1

Answer:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

Answer 2

(b) cost of cementing the roads at 110 per

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