Two crossroads , each of width 4 m , run at right angles through the centre of a rectangular park of length 74 m and breadth 48 m. Find the a. area of crossroads . b. cost of cementing the roads at rs 110 per m².
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Answer:
width =4m
length of first parallel road 74m
area of first road 74×4= 296m²
.
length of second road 48m
area of second road =48×4=192m²
.
area of the common part of cross road with 4 m width that lies at the
center of the park 4x4 = 16m²
.
area of roads = area of first road +area of second cross road−common area
=(296+192)−16
=(296+192)−16=488−16
=472m²
.
cost of the construction per sq.m =Rs.110
.
total cost =472×110 = ₹51920
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