Two crossroads, each of width 4 m, run at right angles through the centre of a rectangular park of length 60 m and width 45 m and parallel to its sides. Find the cost of constructing the roads at the rate of ₹225 per m^2
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width =5 m
length of first parallel road 70 m
area of first road 70×5=350 sq.m
length of second road 45 m
area of second road =45×5=225 sq.m
area of the common part of cross road with 5 m width that lies at the
center of the park 5×5 = 225 sq.m
area of roads = area of first road +area of second cross road−common area
=(350+225)−25=575−25=550sqm
cost of the construction per sq.m =Rs.105
total cost =550×105=Rs 57750
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