Two crossroads, each of width 4 m, runs at right angles through the centre of a rectangular park of length 70 m and breadth 45 m and parallel to the sides of the rectangle. Find the area of the road.
Answers
Answer:
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Step-by-step explanation:
width =4 m
length of first parallel road 70 m
area of first road 70×4=280 sq.m
length of second road=45 m
area of second road =45×4=180 sq.m
area of the common part of cross road with 4 m width that lies at the
center of the park 4×4 = 16 sq.m
area of roads = area of first road +area of second cross road−common area
=(280+180)−16
=460−16
=444 sqm
Answer ::
- The area of road is 444m².
Step - by - step explanation ::
To Find :-
- The area of the road.
Solution :-
Given that,
- Two crossroads, each of width 4 m, runs at right angles through the centre of a rectangular park.
- Length of the park 70m
- Breadth of the park = 45m
ACCORDING THE QUESTION,
The area of first road [ 70m ] :-
➤ 70 x 4
➤ 280m²
The area of second road [ 45m ] :-
➤ 45 x 4
➤ 180m²
As it is given that, each of width 4 m, runs at right angles through the centre of a rectangular park
Therefore, the area of center of the park,
➤ 4 x 4
➤ 16m²
As we know that,
Area of roads = Area of two cross road - Actual area
➤ Area of roads = ( 280m² + 180m²) - 16m²
➤ Area of roads = 460m² - 16m²
➤ Area of roads = 444m²
The area of road is 444m².