Question

Two crossroads, each of width 4 m, runs at right angles through the centre of a rectangular park of length 70 m and breadth 45 m and parallel to the sides of the rectangle. Find the area of the road.​

Answer 1

Answer:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m 

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that  lies at the 

center of the park 5×5 = 225 sq.m 

area of roads = area of first road +area of second cross road−common area

$\sf=(350+225)−25=575−25=550sqm$

       

cost of the construction per sq.m =Rs.105

$\sf \: total \: cost =550×105=Rs 57750$

Answer 2

Answer:

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Step-by-step explanation:

width =4 m

length of first parallel road 70 m

area of first road 70×4=280 sq.m

length of second road=45 m

area of second road =45×4=180 sq.m

area of the common part of cross road with 4 m width that lies at the

center of the park 4×4 = 16 sq.m

area of roads = area of first road +area of second cross road−common area

=(280+180)−16

=460−16

=444 sqm