Question

two crossroads of each width 10 cm cut at right angles through a center of a rectangular park of length 700 cm and breadth 300 cm and parallel to its side.
Find the area of roads, also find the cost of constructing the roads at the rate of ₹50 per metre​

Answer 1

Step-by-step explanation:

Answer

Here, PQ=10m and PS=300m, EH=10m and EF=700m

And KL=10m and KN=10m

Area of roads = Area of PQRS+Area of EFGH−Area of KLMN

[∵ KLMN is taken twice, which is to be subtracted]

=PS×PQ+EF×EH−KL×KN

=(300×10)+(700×10)−(10×10)

=3000+7000−100

=9,900m

2

Area of road in hectares, 1m

2

=

10000

1

hectares

∴9,900m

2

=

10000

9900

=0.99 hectares

Now, Area of park excluding cross roads = Area of park−Area of road

=(AB×AD)−9,900

=(700×300)−9,900

=2,10,000−9,900

=2,00,100 m

2

=

10000

200100

hectares=20.01 hectares.