Question

two crossroads of each width 10 cm cut at right angles through a center of a rectangular park of length 700 cm and breadth 300 cm and parallel to its side.
Find the area of roads, also find the cost of constructing the roads at the rate of rs 50 per metre​

Answer 1

Answer:

Here, PQ = 10 m and PS = 300 m, EH = 10 m and EF = 700 m And KL = 10 m and KN = 10 m

Area of roads

= Area of PQRS + Area of EFGH – Area of KLMN

[∵ KLMN is taken twice, which is to be subtracted]

= PS x PQ + EF x EH – KL x KN

= (300 x 10) + (700 x 10) – (10 x 10)

= 3000 + 7000 – 100

= 9,900 m2

Area of road in hectares,

1 m2 =1/10000 hectares

9,900 m2 =9900/10000

= 0.99 hectares

Now, Area of park excluding cross roads = Area of park – Area of road = (AB x AD) – 9,900

= (700 x 300) – 9,900

= 2,10,000 – 9,900

= 2,00,100 m2

= 200100 hectares = 20.01 hectares