Question

Two crossroads, vertical and horizontal of width 4 m and 3 m respectively run at right angles through
the centre of a rectangular park of length 85 m and breadth 55 m and are parallel to its sides. Find out
Also find out the cost of constructing the crossroads @₹55 per m square​

Answer 1

Correct Question:

Two crossroads, vertical and horizontal of width 4 m and 3 m respectively run at right angles through the center of a rectangular park of length 85 m and breadth 55 m and are parallel to its sides respectively. Find out the total area of the roads.

Also find out the cost of constructing the crossroads @₹55 per m square​

Final Answer:

The total area of the vertical and the horizontal roads is $493m^2$, and the total cost of constructing these two crossroads is ₹27,115.

Given:

There are two crossroads, one is vertical and the other is horizontal having the widths 4 m and 3 m respectively.

They run at right angles through the center of a rectangular park of length 85 m and breadth 55 m and are parallel to its sides.

The cost of constructing the crossroads @₹55 per meter square.

To Find:

The total area of the roads.

Also the total cost of constructing the crossroads.

Explanation:

The area of a rectangle is equal to the product of the length and the breadth of the rectangle.

Alternatively, the area of a rectangle is equal to the product of its any two adjacent sides.

Step 1 of 4

The vertical and horizontal crossroads of widths 4 m and 3 m respectively that run at right angles through the center of a rectangular park of length 85 m and breadth 55 m being parallel to its sides, represent the following rectangles.

• A rectangle with the length 85m and the breadth 4m.
• A rectangle with the length 55m and the breadth 3m.

Step 2 of 4

The area of the rectangle with the length 85m and the breadth 4m is

$=85\times4\\=340m^2$

The area of the rectangle with the length 55m and the breadth 3m is

$=55\times 3\\=165m^2$

The area of the rectangle with the length 4m and the breadth 3m is

$=4\times 3\\=12m^2$

Step 3 of 4

Thus thee total area of the roads is

= (the area of the vertical road + the area of the horizontal road) - (the area overlapped by the two roads)

= (the area of the rectangle with the length 85m and the breadth 4m + the area of the rectangle with the length 55m and the breadth 3m) - (the area of the rectangle with the length 4m and the breadth 3m)

$=(340+165)-12\\=505-12\\=493m^2$

Step 4 of 4

We know that the cost of constructing the crossroad of 1 meter square is ₹55.

So, the cost (in ₹) of constructing the crossroad of 493 meter square is

$=493\times 55\\=27115$

Therefore, the required total area of the vertical and the horizontal roads of widths 4 m and 3 m respectively that run at right angles through the center of a rectangular park of length 85 m and breadth 55 m being parallel to its sides, is $493m^2$, and the required total cost of constructing these two crossroads @₹55 per meter square, is ₹27,115.

Know more from the following links.

https://brainly.in/question/28136612

https://brainly.in/question/666105

#SPJ1